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The value of `a`for the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1,(a > b),`if the extremities of the latus rectum of the ellipse having positiveordinates lie on the parabola `x^2=2(y-2)`is ___ |
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Answer» `(+-ae,b^(2)//a)` are extermities of the latus rectum having positive ordinates. Then. `a^(2)e^(2)=-2((b^(2))/(a)-2) " "(1)` But `b^(2)=a^(2)(1-e^(2))" "(2)` Therefore, from (1) and (2), we get `a^(2)e^(2)-2ae^(2)-4=0` or `ae^(2)(a-2)+2(a-2)=0` `:. (ae^(2)+2)(a-2)=0` Hence, a=2 |
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