1.

The value of acceleration due to gravity at a depth of 1600 km is equal to [Radius of earth = 6400 km]

Answer»

`9.8 MS^(-2)`
`4.9 ms^(-2)`
`19.6 ms^(-2)`
`7.35 m^(-2)`

Solution :GIVEN,
DEPTH (d) = 1600 km
We KNOW that,
`g_(d)=g(1-(d)/(R ))`
Here, `g=9.8m//s^(2)`
R = 6400 km
`g_(d)=g(1-(1600)/(6400))`
`= 9.8 (1-(1)/(4))`
`=9.8((4-1)/(4))=(9.8xx3)/(4)`
`g_(d)=7.35 ms^(-2)`


Discussion

No Comment Found

Related InterviewSolutions