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InterviewSolution
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The value of acceleration due to gravity on the Earth at a distance of 29,000 km from the surgace is `0.3 ms^(-2)`. The value of acceleration due to gravity at the same height on a planet whose mass is `66.70 xx 10^(22)` kg and diameter is 8700 km is _______ `ms_(-2)`. `("Take" G = 6.67 xx 10^(-11) N m^(2) kg^(-2))`A. 0.05B. 0.04C. 0.06D. 0.09 |
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Answer» Correct Answer - B `g = (GM)/(R + h)^(2) = (6.67 xx 10^(-11) xx 66.7 xx 10^(22))/([(4350 + 29000) xx 10^(3)]^(2))` `= (444.889 xx 10^(11))/((33350)^(2)xx10^(6))=0.04 m s^(-2)` |
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