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The value of `[C(7, 0)+C(7, 1)] + [C(7, 1) + C(7, 2)]+ ... + [C(7, 6) + C(7, 7)]`A. 254B. 255C. 256D. 257 |
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Answer» Correct Answer - A `(7_(c_(0)+7_(c_(1))))+(7_(c_(1)+7_(c_(2))))+...+(7_(c_(6)+7_(c_(7))))` We know, `n_(c_(r))+n_(c_(r-1))=.^(n+1)C_(r)` `=8_(c_(1))+8_(c_(2))+...+8_(c_(7))` `=(8_(c_(0))+8_(c_(1))+8_(c_(2))+....+8_(c_(7))+8_(c_(8)))-(8_(c_(0))+8_(c_(8)))=2^(8)-(1+1)` `["Since", n_(c_(0))+ n_(c_(1))+ n_(c_(2))+...+ n_(c_(n))=2^(n)]` = 256 - 2 = 254 |
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