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The value of `cos^(-1)(cos(14pi/6))` isA. `(13pi)/6`B. `(7pi)/6`C. `(5pi)/6`D. `2pi/6`

Answer» Correct Answer - D
Let `cos^(-1)(cos(14pi)/6)=x,` where `x in [0,pi]`.
Then, `cosx=cos(13pi)/6=cos(2pi+2pi/6)=cos2pi/6 rArr x=2pi/6`.


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