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The value of cos2 \((\frac{π}6+x)\) - sin2 \((\frac{π}6-x)\) isA. \(\frac{1}2\) cos 2xB. 0 C. -\(\frac{1}2\)cos2xD.\(\frac{1}2\) |
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Answer» cos2 A – sin2 B = cos(A + B)cos(A - B) = cos \((\frac{π}3)\) cos (2x) = \(\frac{1}2\) cos(2x) |
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