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The value of `DeltaG^(@)`for the phosphorylation of glucose in glycolysis is `15KJ//mol`. Find the value of `K_(eq) "at" 300 K`.A. `e^(6)`B. `._(10)-(6)/(2.303)`C. `(1)/(e^(-6))`D. `._(10)(2.303)/(6)` |
Answer» Correct Answer - B `DeltaG^(@)=-RT"in"K_(eq) InK_(eq)=-6` `15000=-(25)/(3)xx300"In"K_(eq) K_(eq)=e^(-6)` ltbr. `InK_(eq)=-(15000)/(2500)=6` |
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