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The value of `DeltaH_(O-H)` is `109 kcal mol^(-1)`. Then formation of one mole of water in gaseous state from `H(g)` and `O(g)` is accompanied byA. Release of `218 kcal` of enegryB. Release of `109 kcal` of enegryC. Absorption of `218 kcal` of enegryD. Unpredicatable |
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Answer» `H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g)` `DeltaH =- (2 xx Delta_(O-H)H^(Theta))` `DeltaH =- 2 xx 109 =- 218 kcal` |
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