The value of `DeltaH_("transition")` of C (graphite) `rarr` C (diamond) is 1.9 kJ/mol at `25^(@)C`. Entropy of graphite is higher than entropy of diamond. This implies that :A. C (diamond) is more thermodynamically stable than C (graphite) at `25^(@)C`B. C (graphite) is more thermodynamically stable than C (diamond) at `25^(@)C`C. diamond will provide more heat on complete combustion at `25^(@)C`D. `DeltaG_("transition")` of C (diamond) `rarr` C (graphite) is - ve

The value of `DeltaH_("transition")` of C (graphite) `rarr` C (diamond

1.	The value of `DeltaH_("transition")` of C (graphite) `rarr` C (diamond) is 1.9 kJ/mol at `25^(@)C`. Entropy of graphite is higher than entropy of diamond. This implies that :A. C (diamond) is more thermodynamically stable than C (graphite) at `25^(@)C`B. C (graphite) is more thermodynamically stable than C (diamond) at `25^(@)C`C. diamond will provide more heat on complete combustion at `25^(@)C`D. `DeltaG_("transition")` of C (diamond) `rarr` C (graphite) is - ve
Answer» Correct Answer - B::C::D `C("graphite")rarrC("diamond")` `DeltaG = DeltaH - TDeltaS` `=1.9 -298 (-ve)=+ve` Graphite is more stable than diamond thermodynamically `Delta_(r)H=(Delta_(C)H)_(G)-(Delta_(C)H)_(D),(Delta_(C)H)_(G)=-x(Delta_(C)H)_(D)=-y` `1.9 =-x+yimplies y=1.9 +x` Diamond provides more heat on complete combustion in comparison of graphite.

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