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The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)` at `27^(@)C` is `-1366.5 kJ mol^(-1)`. The value of internal energy change for the above reactio at this temperature will beA. `-1371.5 kJ`B. `-1369.0 kJ`C. `-1364.0 kJ`D. `-1361.5kJ` |
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Answer» Correct Answer - C `C_(2)H_(5)OH(l)+3O_(2)(g)to2CO_(2)(g)+3H_(2)O(s)` `Deltan(g)=2-3=1` `DeltaU=DeltaH-Deltan(g)RT=-1366.5 kJ mol^(-1)` `-(-1xx8.314xx10^(-3)xx300kJ mol^(-1))` `=-1366.5+2.4942=-1364 kJ mol^(-1)` |
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