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The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l)` at `27^(@)C` is `-1366.5KJmol^(-1)` . The value of internal energy change for the above reaction at this tempearature will beA. `-1371.5KJ`B. `-1369.0KJ`C. `-1364.0KJ`D. `-1361.5KJ` |
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Answer» Correct Answer - B Relation between `DeltaH` (enthalpy change) and `DeltaE` (internal energy change) is `DeltaH=DeltaE+Deltan_(g)RT` where `Deltan_(g)` =(moles of gaseous products)-(moles of gaseous reactants) For the given reaction, `Deltan_(g)=2-3=-1` implies `-1366.v5=DeltaE=-1xx8.314xx10^(-3)xx300` `:. DeltaE=-1364.0KJmol^(-1)` |
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