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The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)` at `27^(@)C` is `-1366.5 kJ mol^(-1)`. The value of internal energy change for the above reactio at this temperature will beA. `1369.0` KJB. `-1364.0`KJC. `-1361.5 KJ`D. `-1371.5 ` KJ |
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Answer» Correct Answer - B `C_(2)H_(5)OH(l)+3O_(2)(g) rarr 2CO_(2)(g)+3H_(2)O(l)` `Deltan_(g)=2-3 =-1` `DeltaU = DeltaH - Deltan_(g)RT` `" "=-1366.5 -(-1)xx(8.312)/(10^(3))xx 300` `" =-1366.5 + 0.8314xx3 =- 1364 KJ` |
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