The value of f(y) = 5y−4y²+3 when y = 2, is – InterviewSolution

1.

The value of f(y) = 5y−4y²+3 when y = 2, is

Answer»

F(y)=5y-4y2+3

f(2)=5*2-4*2*2+3

=10-16+3

= -6+3

= -3

Step-by-step EXPLANATION:

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