1.

The value of four quantum number for the last e^(-) of atom of element x are n = 7, l = 1, m = + 1 and s = +1//2(or) -1//2 and value of spin magnetic momentum for element 'X' is zero. Element X has two isotopes (I)_(z)X^(A) (II)._(z)X^(B) Given B-A=18 and B-2Z = 18 where A and B are atomic masses and Z is atomic number The value of (A) and (B) respectively are :

Answer»

118 and 136
218 and 236
226 and 244
236 and 254

Solution : Z = 118
B - 2Z = 18
B = 18 + 2Z
B = 254
B - A = 18
A = 236


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