1.

The value of four quantum number for the last electron of atom of element 'X' are n=7, l=1,m=+1 and s=+1/2 or -1/2 and vlaue of spin magnetic momentum for element 'X' is zero element 'X' has two isotopes (I) ""_(Z)^(A)X and(II) ""_(Z)^(B)X. Q. The possible value of all four quantum numbers for 90th electron of atom of element 'X' is:

Answer»

`{:(n,l,m,s),(6,2,0,-1//2):}`
`{:(n,l,m,s),(5,2,-1,+1//2):}`
`{:(n,l,m,s),(6,0,0,+1//2):}`
`{:(n,l,m,s),(5,3,-2,-1//2):}`

SOLUTION :90th `E^(-)` goes to 5f SUBSHELL to POSSIBLE four QUANTUMNUMBER are 5,3,-2 and -1/2 or +1/2.


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