1.

The value of ∆H for cooling 2 moles of an ideal mono atomic gas from 125°C to 25°C at constant pressure will be [given CP = \(\frac{5}{2}\) R] ……(a) -250 R (b) -500 R (c) 500 R (d) +250 R

Answer»

(b) -500 R

Ti = 125°C = 398K 

Tf = 25°C = 298 K 

∆H = nCp (Tf – Ti

∆H = 2 x \(\frac{5}{2}\) R(298 – 398) 

∆H = -500 R



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