1.

The value of k for which 2x*4 plzzzzz see the attachment

Answer»

X-2=0
X=+2
p(x)= 2x^4+3x^3+2kx^2-3x-6
p(2)= (2*2)^4+(3*2)^3+(2K*2)^2-3*2-6
4^4+6^3+4k^2-6-6
256+216+16k-0
472+16k-0
16k = 472
K = 472/16
k =29.5

(k = 29.5)



Discussion

No Comment Found