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The value of m for which \([\{(\frac{1}{{7}^2})^{-2}\}^{-\frac{1}{3}}]^{\frac{1}{4}}\) = 7m, isA. \(-\frac{1}{3}\)B. \(\frac{1}4\)C. -3D. 2 |
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Answer» [{74} -1/3]1/4 = (1/74)1/3 × 1/4 = (1/7)1/3 = 7m = 7-1/3 = 7m = m = -1/3 |
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