1.

The value of m for which \([\{(\frac{1}{{7}^2})^{-2}\}^{-\frac{1}{3}}]^{\frac{1}{4}}\) = 7m, isA. \(-\frac{1}{3}\)B. \(\frac{1}4\)C. -3D. 2

Answer»

[{74} -1/3]1/4

= (1/74)1/3 × 1/4

= (1/7)1/3 = 7m

= 7-1/3 = 7m

= m = -1/3



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