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The value of `m` for which the line `(x-1)/2=(y-1)/3=(z-1)/m` is perpendicular to normal to the plane `vecr.(2hati+3hatj+4hatk)=0` isA. `-13/4`B. `-17/4`C. `4`D. none of these |
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Answer» Correct Answer - A Given line is parallel to the vector `vecb=2hati+3hatj+mhatk` and given plane is normal to `vecn=2hati+3hatj+hatk`. If `vecb` and `vecn` are perpendicular then `vecb.vecn=0implies4+9+4m=0impliesm=-13/4` |
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