1.

The value of `sec^(2)-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)` isA. 1B. 2C. `-1`D. 0

Answer» Correct Answer - a
`sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)`
`=sec^(2)theta-(sin^(2)theta( 1-2sin^(2)theta))/(cos^(2)theta(2cos^(2)theta-1))`
`[cos^(2)theta-sin^(2)theta=2cos^(2)theta-1=1-2sin^(2)theta]`
` =sec^(@)theta-tan^(2)theta=1`


Discussion

No Comment Found

Related InterviewSolutions