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The value of `sec^(2)-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)` isA. 1B. 2C. `-1`D. 0 |
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Answer» Correct Answer - a `sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)` `=sec^(2)theta-(sin^(2)theta( 1-2sin^(2)theta))/(cos^(2)theta(2cos^(2)theta-1))` `[cos^(2)theta-sin^(2)theta=2cos^(2)theta-1=1-2sin^(2)theta]` ` =sec^(@)theta-tan^(2)theta=1` |
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