1.

The value of `sin^(2)22^(@)+sin^(2)68^(@)+cot^(2)30^(@)` isA. 43589B. 43528C. 3D. 4

Answer» Correct Answer - d
Given
`rArrsin^(2)22^(@)+sin68^(@)+cot^(2)30^(@)`
`rArrcos^(2)68^(@)+sin^(2)68^(@)+cot^(2)30^(@)`
`{sin(90-theta)costheta cos (90-theta)=sin theta}`
`rArr1+cot^(2)30^(@)`
`rArr1+(sqrt(3))^(2)[becausecot30^(@)=sqrt(3)]`
`rarr4`


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