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The value of `sin^(2)22^(@)+sin^(2)68^(@)+cot^(2)30^(@)` isA. 43589B. 43528C. 3D. 4 |
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Answer» Correct Answer - d Given `rArrsin^(2)22^(@)+sin68^(@)+cot^(2)30^(@)` `rArrcos^(2)68^(@)+sin^(2)68^(@)+cot^(2)30^(@)` `{sin(90-theta)costheta cos (90-theta)=sin theta}` `rArr1+cot^(2)30^(@)` `rArr1+(sqrt(3))^(2)[becausecot30^(@)=sqrt(3)]` `rarr4` |
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