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The value of sin (45° + θ) – cos (45° – θ) is(A) 2 cosθ (B) 2 sinθ (C) 1 (D) 0 |
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Answer» Answer is (D) sin (45° + ) – cos (45° – ) = sin (45° + ) – sin (90° – (45° – )) = sin (45° + ) – sin (45°+ ) = 0 |
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