1.

The value of sin (45° + θ) – cos (45° – θ) is(A) 2 cosθ (B) 2 sinθ (C) 1 (D) 0

Answer»

Answer is (D)

sin (45° + ) – cos (45° – ) = sin (45° + ) – sin (90° – (45° – ))

= sin (45° + ) – sin (45°+ ) = 0



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