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The value of `{(sqrt(2) +1)^(5) + (sqrt(2) -1)^(5)}` ,isA. 58B. `58sqrt(2)`C. 42D. `42sqrt(2)` |
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Answer» Correct Answer - b Using binomial expansion, we have `(sqrt(2) +1)^(5) + (sqrt(2)-1)^(5) = 2 {(sqrt(2))^(5) +10(sqrt(2))^(3) + 5sqrt(2)} ` `(sqrt(2) +1)^(5) + (sqrt(2)-1)^(5) = 2{4sqrt(2) +20sqrt(2) + 5sqrt(2)} = 5sqrt(2)`. |
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