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The value of `sum_(0leiltjle5) sum(""^(5)C_(j))(""^(j)C_(i))` is equal to `"_____"` |
Answer» Correct Answer - 211 `underset(0leiltjle5)(sumsum)(.^(5)C_(j))(.^(j)C_(i))` `=.^(5)C_(1)..^(1)C_(0)+.^(5)C_(2)(.^(2)C_(0)+.^(2)C_(1))+"......"+.^(5)C_(5)(.^(5)C_(0)+.^(5)C_(1)+"...."+.^(5)C_(5))` `= .^(5)C_(1)(2^(1)-1)+.^(5)C_(2)(2^(2)-1)+"....."+.^(5)C_(5)(2^(5)-1)` `= (.^(5)C_(1).2^(1)+.^(5)C_(2).2^(2)+".....".+.^(5)C_(5).2^(5))-(.^(5)C_(1)+.^(5)C_(2)+"...."+.^(5)C_(5))` `= [(1+2)^(5)-1][2^(5)-1]` `= 3^(5)-2^(5)` `= 243-32=211` |
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