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The value of `sum_(i=1)^(n) sum_(j=1)^(i) sum_(k=1)^(j) 1` isA. `sumn`B. `sumn^(2)`C. `sumn^(3)`D. none of these |
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Answer» Correct Answer - D We have, `underset(i=1)overset(n)sumunderset(j=1)overset(i)sumunderset(k=1)overset(j)sum1=underset(i=1)overset(n)sumunderset(j=1)overset(i)sumj` `=underset(i=1)overset(n)sum(1+2+. . . .i)` `underset(i=1)overset(n)sum(i(i+1))/(2)=(1)/(2){underset(i=1)overset(n)sumi^(2)+underset(i=1)overset(n)sumi}` `=(1)/(2){(n(n+1)(2n+1))/(6)+(n(+1))/(2)}` `=(n(n+1))/(4){(2n+1)/(3)+1}=(n(n+1)(n+2))/(6)` |
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