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The value of `sum_(r=0)^(10) (r)""^(20)C_(r)` is equal toA. `20(2^(18)+.^(19)C_(10))`B. `10(2^(18)+.^(18)C_(10))`C. `20(2^(16)+.^(19)C_(11))`D. `10(2^(18)+.^(19)C_(11))` |
Answer» Correct Answer - A `underset(r=0)overset(10)sum(r).^(20)C_(r) = underset(r=1)overset(10)sum20 xx .^(19)C_(r-1)` `= 20(.^(19)C_(0) + .^(19)C_(1) + "......"+ .^(19)C_(10))` `= 20 (.^(19)C_(0) +.^(19)C_(1) + "......" + .^(19)C_(10))` `= 20(1/2 xx 2^(10) + .^(19)C_(10))` `= 20(2^(18)+.^(19)C_(10))` |
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