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The value of `sum_(r=0)^10cos^3((rpi)/3)` isA. `1//4`B. `1//8`C. `-1//4`D. `-1//8` |
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Answer» Correct Answer - D `sum_(r=0)^(10)cos^(3)((rpi)/(3))=(1)/(4)sum_(r=0)^(10)(3cos((rpi)/(3))+cos rpi)` `=(1)/(4)[3(cos0+cos((pi)/(3))+.......+cos((10pi)/(3)))+(1-1+.....-1+1])` `=(3)/(4)((cos((10pi)/(6))sin((11pi)/(6)))/(sin((pi)/(6))))+(1)/(4)=(1)/(8)` |
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