1.

The value of the 3rd term of the expression 4n+1​

Answer»

Tn=4n+1  

SUM =∑  15/ k=1  (4k+1)

=∑  

k=1

15

​  

4k+∑  

k=1

15

​  

(1)

=4[1+2+3+4+..........+15]

=4×  

2

15×(15+1)

​  

+15

=480+15

=  

495



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