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The value of the 3rd term of the expression 4n+1 |
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Answer» Tn=4n+1 =∑ k=1 15 4k+∑ k=1 15 (1) =4[1+2+3+4+..........+15] =4× 2 15×(15+1) +15 =480+15 = 495 |
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