1.

The value of the limiting molar conductivity (Λº) for NaCl, HCl and NaOAc are 126.4, 425.9 and 91.0 S cm2 mol–1, respectively. For HOAc, Λº in S cm2 mol–1 is(A) 390.5 (B) 299.5 (C) 208.5 (D) 217.4 

Answer»

Correct Option :-  (A) 390.5

Explanation :-

Λ (HOAc) = Λº(NaOAc) + Λº(HCl) – Λº(NaCl) 

 = 91 + 425.9 – 126.4 = 390.5 



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