The value of wavelength in the lyman series is given as lambda=(913.4 n_i^2)/(n_i^2-1)Å Calculate the wavelength corresponding to transition from energy level 2,3 and 4. Does wavelength decreases or increase.

The value of wavelength in the lyman series is given as lambda=(913.4

1.	The value of wavelength in the lyman series is given as lambda=(913.4 n_i^2)/(n_i^2-1)Å Calculate the wavelength corresponding to transition from energy level 2,3 and 4. Does wavelength decreases or increase.
Answer» SOLUTION :`lambda_(21) =(913.4 XX 2^2)/(2^2-1)=1218 Å` `lambda_(31)=(913.4 xx 3^2)/(3^2-1)=1028Å` `lambda_(41)=(913.4xx4^2)/(4^2-1)=974.3 Å` `lambda_(41) LT lambda_(31) lt lambda_(21)`

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The value of wavelength in the lyman series is given as lambda=(913.4 n_i^2)/(n_i^2-1)Å Calculate the wavelength corresponding to transition from energy level 2,3 and 4. Does wavelength decreases or increase.

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