The value of ∫ [x^2 √(1 - x^2)] dx from 0 to 1 is (1) 2(2) pi(3) p – InterviewSolution

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1.	The value of ∫ [x^2 √(1 - x^2)] dx from 0 to 1 is (1) 2(2) pi(3) pi/2(4) pi/4
Answer» The value of ∫ [x^2 √(1 - x^2)] dx from 0 to 1 is (1) 2 (2) pi (3) pi/2 (4) pi/4

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