The value ofsin(n+1) A – sin(n-1) Acos(n+1) A + cos(n-1) Ais

1.	The value ofsin(n+1) A – sin(n-1) Acos(n+1) A + cos(n-1) Ais
Answer» Answer: As, COS(A-B) = cosAcosB+sinAsinB....(1) Now LET, A= (n+1)A B=(n-1)A then by eq (1) we can say that cos[(n+1)A - (n-1)A]= sin(n+1)A.sin(n-1)A+cos(n+1)A.cos(n-1)A in lhs, =cos[An+A-(An-A)] =cos 2A hence proved hope it helps uh... Step-by-step explanation: *MissInvisible*...✌️

Answer»

Answer:

As,

COS(A-B) = cosAcosB+sinAsinB....(1)

Now LET,

A= (n+1)A

B=(n-1)A

then by eq (1) we can say that

cos[(n+1)A - (n-1)A]= sin(n+1)A.sin(n-1)A+cos(n+1)A.cos(n-1)A

in lhs,

=cos[An+A-(An-A)]

=cos 2A

hence proved

hope it helps uh...

Step-by-step explanation:

MissInvisible...✌️

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