1.

The values of and y' are s values of x and y' which satisfy near equation x + 3y = 10 are​

Answer»

Step-by-step EXPLANATION:

X+3y=10

Subtract x from both SIDES.

3y=10-x

DIVIDE both sides by 3.

\frac{3y}{3}=\frac{10-x}{3}

y=\frac{10-x}{3}

x=10-3y



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