The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.3 at `26.7^@C`. Calculate the number of moles of `NO_2` I `100g` of the mixture.A. `0.2`B. `0.4`C. `0.8`D. `1.6`

The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.

1.	The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.3 at `26.7^@C`. Calculate the number of moles of `NO_2` I `100g` of the mixture.A. `0.2`B. `0.4`C. `0.8`D. `1.6`
Answer» Correct Answer - B `alpha=(D-d)/(d)` D= Vapour density before dissociation d= vapour density after dissociation `N_(2)O_(4) hArr 2NO_(2)` Vapour density of `N_(2)O_(4)` before dissociation `(D)=(14xx2+16xx4)/(2)=92/2=46` Vapour density after dissociation `(d)=38.3` `:. alpha=(46-38.3)/38.3=0.2` `{:(,N_(2)O_(4),hArr,2NO_(2)),("Initial",1,,0),("At equilibrium",1-alpha,,2alpha):}` Number of moles of `NO_(2)` at eq. `=2alpha=2xx0.2=0.4`

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The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.3 at `26.7^@C`. Calculate the number of moles of `NO_2` I `100g` of the mixture.A. `0.2`B. `0.4`C. `0.8`D. `1.6`

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