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The vapour density of mixture consisting of `NO_2` and `N_2O_4` is 38.3 at `26.7^@C`. Calculate the number of moles of `NO_2` I `100g` of the mixture. |
Answer» Molecular weight of the mixture`=38.3xx2=76.6` Molecular weight of `NO_2=46 and N_2O_4=92` Let the number of moles of `NO_2` be x. Number of moles of `N_2O_4=(100-46x)/(92)` `x+(100-46x)/(92)=(100)/(76.6)impliesx=0.438mol` |
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