1.

The vapour pressure of a solvent decreases by 10 mm of mercury when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction or the solvent if the decrease in vapour presssure is to be 20 mm of mercury?

Answer»

0.8
0.6
0.4
0.4

Solution :`Deltap//p^(@)=x_(2)," HENCE, "Deltap//Deltap'=x_(2)//x_(2)'.i.e., 10//20`
`=0.2//x_(2)'or x_(2)'=0.4." Hence, "x_(1)'=1-0.4=0.6.`


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