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| 1. |
The vapour pressure of liquid Hg at `433` K is`5` mm Hg . Calculate the free energy change accompanying the expansion of one mole of Hg vapour in equilibrium with liquid at `433` K to a pressure of `750` mm Hg at the same temperature assuming the vapour bahaves like an ideal monoatomic gas in KJ `"mole"^(-1)` . (Approximate integer and `e^(5) = 150`) |
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