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The vapour pressure of water at `20^(@)C is 17.54mm`. When 20g of non - ionic substance is dissolved in 100g of water, the vapour pressure is lowered by `0.30mm`. What is the molecular mass of the substance ?A. `200.8`B. `206.88`C. `210.5`D. `215.2` |
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Answer» Correct Answer - B Relative lowering in vapour pressure, `(p^(@)-p_s)/(p^(@))=(x_(2))/(x_(2)+x_(1))=(w//m)/(w/m+W/M)` `(0.30mm)/(17.54mm)=(20//m)/(20//m+100//18)` `rArrm=206.88` |
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