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The variance of first n natural number is:A. `(n^(2)-1)/(12)`B. `(n^(2)-1)/(6)`C. `(n^(2)+1)/(6)`D. `(n^(2)+1)/(12)` |
Answer» Correct Answer - A Variance`=(SD)^(2)=(1)/(n)sumx^(2)-((sum x)/(n))^(2), (because overline(x)=(sum x)/(n))` `=(n(n+1)(2n+1))/(6n)-((n(n+1))/(2n))^(2)=(n^(2)-1)/(12)` |
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