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The variance offirst 50 even natural numbers is(1) `(833)/4`(2) 833(3) 437(4) `(437)/4` |
Answer» `2,4,6,8,......,98,100` `sigma^2 = (sum x_1^2)/n - (bar(.x))^2` `(2^2 + 4^2 + 6^2 + .... + 100^2)/50 - ((2+4+6 + ....+100)/50)^2` `i_1 = (2^2+ 4^2 + 6^2 + ....+100^2)/50` `= 2^2(1^2 + 2^2 + 3^2+ ...+50^2)/50` `= 2^2/50 xx 50(50+1)(100+1)` `=3434` `i_2 = ((2+4+6+.....+100)/50)^2` `= ((50 xx (2+100)/2)/50)^2` `= (51)^2` `sigma^2 = 3434 - 2661 = 833` Answer |
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