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The vector ⎡⎢⎣12−1⎤⎥⎦ is an eigen vector of A=⎡⎢⎣−22−321−6−1−20⎤⎥⎦. The corresponding eigen value of A is _____. |
Answer» The vector ⎡⎢⎣12−1⎤⎥⎦ is an eigen vector of A=⎡⎢⎣−22−321−6−1−20⎤⎥⎦. The corresponding eigen value of A is _____. |
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