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The vector equation of a plane passing through a point having position vector `2hati+3hatj-4hatk` and perpendicular to the vector `2hati-hatj+2hatk`, isA. `vecr.(2hati-hatj+2hatk)=7`B. `vecr.(2hati-hatj+2hatk)=-7`C. `vecr.(2hati-hatj+2hatk=4`D. none of these |
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Answer» Correct Answer - B We know that the vector equation of plane passing through a point `veca` and normal to `vecn` is `(vecr-veca).vecn=0` or `vecr.vecn=veca.vecn` Here `veca=2hati+3hatj-4hatk` and `vecn=2hati-hatj+2hatk` So the equation of the required plane is `vecr.(2hati-hatj+2hatk)=(2hati+3hatj-4hatk).(2hati-hatj+2hatk)` `impliesvecr.(2hati-hatj+2hatk)=-7` |
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