1.

The vector equation of line 2x – 1 = 3y + 2 = z - 2 is(a) \(\bar{r} = \left(\frac{1}{2}\bar{i} - \frac{2}{3}\bar{j}+ 2\bar{k}\right)\) + \(\lambda(3\bar{i} + 2\bar{j} + 6\bar{k})\)(b) \(\bar{r} = \bar{i} - \bar{j} + (2\bar{i}+\bar{j} + \bar{k})\)(c) \(\bar{r} = \left(\frac{1}{2}\bar{i} - \bar{j}\right)\) + \(\lambda(\bar{i} - 2\bar{j} + 6\bar{k})\)(d) \(\bar{r} = (\bar{i} + \bar{j})\) + \(\lambda(\bar{i} - 2\bar{j} + 6\bar{k})\)

Answer»

Correct answer is  (a) \(\bar{r} = \left(\frac{1}{2}\bar{i} - \frac{2}{3}\bar{j}+ 2\bar{k}\right)\) + \(\lambda(3\bar{i} + 2\bar{j} + 6\bar{k})\)



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