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The vectors `2 hati + 3 hatj , 5 hati + 6hatj and 8 hatj + lambda hatj ` have their initial points at (1, 1). The value of `lambda` so that the vectors terminate on one straight line, is |
Answer» Since the vectors `2hati+3hatj and 5hati+6hatj` have (1, 1) as the initial point, their terminal points are (3, 4) and (6, 7), respectively. The equation of the line joining these two points is `x-y+1=0`. The terminal point of `8hati+lamdahatj` is `(9, lamda + 1)`. Since the vectors terminate on the same straight line, `(9, lamda+1)` lies on `x-y+1=0`. Therefore, `" "9-lamda-1+1=0` or `" "lamda=9` |
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