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The velocity filter of a mass spectrometer employs an electric field strength of 1.0 xx 10^(2) V/m and a perpendicular magnetic induction of 2.0 xx 10^(-4)T. The induction of the deflecting uniform magnolie Deld which is perpendicular to the beam is 9.0 xx 10^(-2) T. Ions with similar arges and with mass numbers 20 and 22 pass through the filter and make a 180^@ turn in the deflecting field (Fig. 28.12). What is the distance between the points S_1 and S_2?

Answer»


SOLUTION :The distance of interest is equal to the DIFFERENCE in the diameters of the ionic orbits `A= 2(R_(2)-R_(1)).` The speeds of both ions are IDENTICAL and are determined by the conditions of their passage through the velocity filter: u= E/B. The radius of the orbit is `R=mu//qB_(0)`. THEREFORE the difference sought is `triangle=(2 E)/(qBB_(0)) (m_(2)-m_(1))`
We obtain the difference sought by assurning the ion to be singly ionized, ie. by putting: q= e.


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