1.

The velocity of a 2 kg body is changed from (4hati +3hatj) ms^(-1) to 6hat ms^(-1). The work done on the body is

Answer»

9 J
11 J
1 J
0 J

Solution :Here velocity
`v_1=sqrt((4)^2+(3)^2)=5 ms^(-1)`
and velocity `v_2=6 ms^(-1)`
NowW=increase in K.E.
`=1/2m(v_2^2-v_1^2)`
=`1/2xx2(36-25)`
=11 J


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