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The velocity of a body of mass 2 kg is given byvecupsilon=(2t overset(wedge)(i)+t^(2)overset(wedge)(j))Find the momentum of the body after 2 seconds. |
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Answer» `(8overset(wedge)(i)+8overset(wedge)(j))KG ms^(-1)` `vecupsilon=(2thati+t^(2)hatj)` velocity after 2 sec `vecupsilon`= `vecupsilon_(t)=(2xx2hati+4hatj)` `(4hati+4hatj)` MONENTUM`vecp_(t)=m vecupsilon_(t)` `=2(4hati+4hatj)` |
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