1.

The velocity of a particle is v=6hat(i)+2hat(j)-2hat(k).The component of the velocity parallel to vectora=hat(i)+hat(j)+hat(k)in vector form is

Answer»

`6HAT(i)+2hat(J)+2hat(k)`
`2hat(i)+2hat(j)+2hat(k)`
`hat(i)+hat(j)+hat(k)`
`6hat(i)+2hat(j)-2hat(k)`

Solution :(B) Magnitude of component of v along a
`=(v.a)/(a)=(6+2-2)/(sqrt(3))=2sqrt(3)`
`"Now"hat(a)=(hat(i)+hat(j)+hat(k))/(sqrt(3))`
:.Component in VECTOR form
`=2sqrt(3)hat(a)`
`=(2hat(i)+2hat(j)+2hat(k))`


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