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The velocity of a particle moving along the xaxis is given by `v=v_(0)+lambdax`, where `v_(0)` and lambda are constant. Find the velocity in terms of t. |
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Answer» `v=v_(0)+lambdax` `(dv)/(dt)=0+lambda(dx)/(dt)=lambdav` `a=lambdav` At `x=0, v=v_(0)` `a=lambdav` `(dv)/(dt)=lambdav` `int_(v_(0))^(v)(dv)/v=lambda int_(0)^(t) dt` `|log_(e)v|_(v_(0))^(v)=lambda|t|_(0)^(t)` `log_(e)v-log_(e)v_(0)=lambdat` `log_(e)(v/v_(0))=lambdat` `v/v_(0)=e^(lambdat)` `v=v_(0)e^(lambdat)` |
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