1.

The velocity of an electron in Bohr's first orbital of la H-atom is 2.16xx10^(6)ms^(-1). Its velocity in the second orbit would be

Answer»

`1.08xx10^(6)MS^(-1)`
`0.54xx10^(6)ms^(-1)`
`4.32xx10^(6)ms^(-1)`
`8.64xx10^(6)ms^(-1)`

Solution :VELOCITY `prop 1/N`
`(v_(2))/(v_(1))=(n_(1))/(n_(2))`
`:.v_(2)=v_(1)xx(n_(1))/(n_(2))=2.16xx10^(2)xx1/2`
`=1.08xx10^(5)ms^(-1)`


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